JEE MAIN - Chemistry (2013 (Offline) - No. 5)
Arrange the following compounds in order of decreasing acidity :
_en_5_1.png)
$${\rm I}{\rm I} > {\rm I}V > {\rm I} > {\rm I}{\rm I}{\rm I}$$
$${\rm I} > {\rm I}{\rm I} > {\rm I}{\rm I}{\rm I} > {\rm I}V$$
$${\rm I}{\rm I}{\rm I} > {\rm I} > {\rm I}{\rm I} > {\rm I}V$$
$${\rm I}V > {\rm I}{\rm I}{\rm I} > {\rm I} > {\rm I}{\rm I}$$
Explicação
Electron withdrawing substituents like $$ - N{O_2},\,Cl$$ increase the acidity of phenol while electron releasing substituents like $$ - C{H_3}, - OC{H_3}$$ decreases acidity.
Hence the correct order of acidity will be
_en_5_2.png)
Further $$\left( { - {\rm I}} \right)N{O_2} > \left( { - {\rm I}} \right)Cl\,\,$$ and $$\,\,\left( { + {\rm I}} \right)C{H_3} > \left( { + {\rm I}} \right)OC{H_3}$$
Hence the correct order of acidity will be
Further $$\left( { - {\rm I}} \right)N{O_2} > \left( { - {\rm I}} \right)Cl\,\,$$ and $$\,\,\left( { + {\rm I}} \right)C{H_3} > \left( { + {\rm I}} \right)OC{H_3}$$